Answer :

**To find:** Original price of toy.

**Method Used:**

To solve the quadratic equation by factorisation method, follow the steps:

1) Multiply the coefficient of x^{2} and constant term.

2) factorise the result obtained in step 1.

3) Now choose the pair of factors in such a way that after adding or subtracting(splitting) them

You get coefficient of x.

**Explanation:**

Let the original price of the toy be ‘a’.

Given, when the list price of a toy is reduced by Rs. 2, a person can buy 2 toys more for Rs. 360.

Number of toys he can buy at original price for

Number of toys he can buy at reduced price

According to the question,

⇒ 360a = (a – 2) (360 + 2a)

⇒ 360a = 360a + 2a^{2} – 720 – 4a

⇒ a^{2} – 2a – 360 = 0

⇒ a^{2} – 20a + 18a – 360 = 0

⇒ a (a – 20) + 18(a – 20) = 0

⇒ (a + 18) (a – 20) = 0

⇒ a = -18 and a = 20

As price cannot be negative.

⇒ a = Rs. 20

Hence price of toy is **Rs 20.**

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