Q. 21

If the list price

Answer :

To find: Original price of toy.


Method Used:


To solve the quadratic equation by factorisation method, follow the steps:


1) Multiply the coefficient of x2 and constant term.


2) factorise the result obtained in step 1.


3) Now choose the pair of factors in such a way that after adding or subtracting(splitting) them


You get coefficient of x.


Explanation:


Let the original price of the toy be ‘a’.


Given, when the list price of a toy is reduced by Rs. 2, a person can buy 2 toys more for Rs. 360.


Number of toys he can buy at original price for


Number of toys he can buy at reduced price


According to the question,




360a = (a – 2) (360 + 2a)


360a = 360a + 2a2 – 720 – 4a


a2 – 2a – 360 = 0


a2 – 20a + 18a – 360 = 0


a (a – 20) + 18(a – 20) = 0


(a + 18) (a – 20) = 0


a = -18 and a = 20


As price cannot be negative.


a = Rs. 20


Hence price of toy is Rs 20.


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