Q. 35.0( 2 Votes )

# Write the area of the circle passing through (- 2, 6) and having its centre at (1, 2).

Answer :

We need to find the area of the circle passing through (- 2,6) and having a centre at (1,2).

We know that the radius of the circle is the distance between the centre and any point on the radius. So, we find the radius of the circle.

We know that the distance between the two points (x_{1},y_{1}) and (x_{2},y_{2}) is .

Let us assume r is the radius of the circle.

⇒

⇒

⇒

⇒ r = √25

⇒ r = 5

We know that the area of the circle is r^{2}.

⇒ Area(A) = π(5)^{2}

⇒ A = π(25)

∴The area of the circle is 25π.

Rate this question :

The equation of the circle which touches the axes of coordinates and the line and whose centres lie in the first quadrant is x^{2} + y^{2} – 2cx – 2cy + c^{2} = 0, where c is equal to

Find the equation of the circle which circumscribes the triangle formed by the lines:

y = x + 2, 3y = 4x and 2y = 3x

RD Sharma - MathematicsThe equation of the circle concentric with x^{2} + y^{2} – 3x + 4y – c = 0 and passing through (- 1, - 2) is

Find the equation of the circle which passes through (3, - 2), (- 2, 0) and has its centre on the line 2x – y = 3.

RD Sharma - MathematicsShow that the points (5, 5), (6, 4), (- 2, 4) and (7, 1) all lie on a circle, and find its equation, centre, and radius.

RD Sharma - MathematicsIf the circle x^{2} + y^{2} + 2ax + 8y + 16 = 0 touches x - axis, then the value of a is

Find the equation of the circle which passes through the points (3, 7), (5, 5) and has its centre on line x – 4y = 1.

RD Sharma - MathematicsFind the equation of the circle passing through the points :

(5, - 8), (- 2, 9) and (2, 1)

RD Sharma - MathematicsThe circle x^{2} + y^{2} + 2gx + 2 fy + c = 0 does not intersect x - axis, if

Find the equation of the circle passing through the points :

(1, 2), (3, - 4) and (5, - 6)

RD Sharma - Mathematics