Q. 34.6( 9 Votes )

Find the equation

Answer :

Given that we need to find the equation of the circle whose centre is (1, 2) and passing through the point (4, 6).



We know that the radius of the circle is the distance between the centre and any point on the radius. So, we find the radius of the circle.


We know that the distance between the two points (x1,y1) and (x2,y2) is .


Let us assume r is the radius of the circle.






r = 5 units ..... (1)


We know that the equation of the circle with centre (p, q) and having radius ‘r’ is given by:


(x - p)2 + (y - q)2 = r2


Now we substitute the corresponding values in the equation:


(x - 1)2 + (y - 2)2 = 52


x2 - 2x + 1 + y2 - 4y + 4 = 25


x2 + y2 - 2x - 4y - 20 = 0.


The equation of the circle is x2 + y2 - 2x - 4y - 20 = 0.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Find the equationRD Sharma - Mathematics

Find the equationRD Sharma - Mathematics

Find the equationRD Sharma - Mathematics

If the lineRD Sharma - Mathematics

The sides of a sqRD Sharma - Mathematics

The line 2xRD Sharma - Mathematics

ABCD is a sRD Sharma - Mathematics

The circle RD Sharma - Mathematics

Find the equationRD Sharma - Mathematics

Find the equationRD Sharma - Mathematics