Q. 1 A4.6( 22 Votes )

# Find the equation

(i) Given that we need to find the equation of the circle with centre ( - 2, 3) and radius 4.

We know that the equation of the circle with centre (p, q) and radius ‘r’ is given by:

(x - p)2 + (y - q)2 = r2

Now we substitute the corresponding values in the equation:

(x - ( - 2))2 + (y - 3)2 = 42

(x + 2)2 + (y - 3)2 = 16

x2 + 4x + 4 + y2 - 6y + 9 = 16

x2 + y2 + 4x - 6y - 3 = 0

The equation of the circle is x2 + y2 + 4x - 6y - 3 = 0.

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