Given that we need to find the centre and radius of the given circle x2 + y2 - x + 2y - 3 = 0.
We know that the standard equation of a circle with centre (a, b) and having radius ‘r’ is given by:
⇒ (x - a)2 + (y - b)2 = r2 - - - - - (1)
Let us convert given circle’s equation into the standard form.
⇒ x2 + y2 - x + 2y - 3 = 0
⇒ - - - - - (2)
Comparing (2) with (1), we get
⇒ Centre = (, - 1) and radius =
∴The centre and radius of the circle is (, - 1) and.
Rate this question :
If the lineRD Sharma - Mathematics
The sides of a sqRD Sharma - Mathematics
The line 2xRD Sharma - Mathematics
ABCD is a sRD Sharma - Mathematics
The circleRD Sharma - Mathematics