Answer :
Given that we need to find the centre and radius of the given circle x2 + y2 - x + 2y - 3 = 0.
We know that the standard equation of a circle with centre (a, b) and having radius ‘r’ is given by:
⇒ (x - a)2 + (y - b)2 = r2 - - - - - (1)
Let us convert given circle’s equation into the standard form.
⇒ x2 + y2 - x + 2y - 3 = 0
⇒
⇒
⇒ - - - - - (2)
Comparing (2) with (1), we get
⇒ Centre = (, - 1) and radius =
∴The centre and radius of the circle is (, - 1) and
.
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
Find the equation
RD Sharma - MathematicsFind the equation
RD Sharma - MathematicsFind the equation
RD Sharma - MathematicsIf the line
RD Sharma - MathematicsThe sides of a sq
RD Sharma - MathematicsThe line 2x
RD Sharma - MathematicsABCD is a s
RD Sharma - MathematicsThe circle
RD Sharma - MathematicsFind the equation
RD Sharma - MathematicsFind the equation
RD Sharma - Mathematics