Given that we need to find the equation of the circle with centre (a, b) and radius .
We know that the equation of the circle with centre (p, q) and radius ‘r’ is given by:
⇒ (x - p)2 + (y - q)2 = r2
Now we substitute the corresponding values in the equation:
⇒ (x - a)2 + (y - b)2 =
⇒ x2 - 2ax + a2 + y2 - 2by + b2 = a2 + b2
⇒ x2 + y2 - 2ax - 2by = 0
∴The equation of the circle is x2 + y2 - 2ax - 2by = 0.
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