Q. 13 E4.3( 11 Votes )

If sec 5A = cosec (A + 36°) and 5A is a positive acute angle, let us find the value of A.

Answer :

Given, sec5A = cosec(A + 36°)


And 5A is positive acute angle


sec5A = cosec(A + 36°)


cosec(90° - 5A) = cosec(A + 36°)


[secθ = cosec(90 - θ)]


90 - 5A = A + 36


90 - 36 = 6A


6A = 54


A = 9


Hence, the value of A is 9


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