Q. 13 E4.3( 11 Votes )

# If sec 5A = cosec (A + 36°) and 5A is a positive acute angle, let us find the value of A.

Given, sec5A = cosec(A + 36°)

And 5A is positive acute angle

sec5A = cosec(A + 36°)

cosec(90° - 5A) = cosec(A + 36°)

[secθ = cosec(90 - θ)]

90 - 5A = A + 36

90 - 36 = 6A

6A = 54

A = 9

Hence, the value of A is 9

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