Q. 2 A4.4( 7 Votes )

# Let us show that:sin66° - cos24° = 0

Given, sin66° - cos24° = 0

Need to prove the given equation as zero

we know that cos(90 - θ) = sinθ

cos24° = cos(90 - 66)°

= sin66° - - - eq (1)

sin66° - cos24° = 0

[substitute eq(1)]

sin66° - sin66° = 0

Hence, LHS = RHS

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