Q. 13 B4.5( 10 Votes )

# If tan 4θ × tan 6θ = 1 and 6θ is a positive acute angle, let us find the value of θ.

Given, 6θ as a positive acute angle

tan4θ tan6θ = 1

tan4θ cot(90 - 6θ) = 1

cot(90 - 6θ) = cot4θ

90 - 6θ = 4θ

10θ = 90

θ = 9

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