# ABCD is a rectangular figure, joining A,C let us prove that(i) tan∠ACD = cot∠ACB(ii) tan2∠CAD + 1 =

AC is the diagonal line joining ABCD

(i) tanACD = cotACB

ACD + ACB = 90

tanACD

= tan(90 - ACB)

= cotACB

[ADC = BAC, from the properties]

= cosec2BAC

=

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Quiz | Task on Trigonometric Ratios46 mins
T- Ratios of Specified Angles58 mins
Quiz on Trigonometric Ratios31 mins
Trigonometric Identities33 mins
Champ Quiz | Trigonometric Identities33 mins
Testing the T- Ratios of Specified Angles57 mins
NCERT | Trigonometric Identities52 mins
Trigonometric Identities44 mins
Trick to learn all Trigonometric Formulae28 mins
Solving NCERT Questions on Trigonometric Identities56 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses