Q. 7

# Let us show that cosec222°cot268° = sin222° + sin268° + cot268°

Given, cosec222°cot268° = sin222° + sin268° + cot268°

sin222° + sin268° + cot268°

= sin222° + sin2(90 - 22)° + cot268°

= sin222° + cos222° + cot268°

= 1 + cot268°

= cosec268°

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