Q. 44.1( 15 Votes )

# If sin 17° = , let us show that sec 10° - sin73° =

Answer :

Given,

To show,

[sec θ =

⇒

⇒ sin73° = sin(90 - 17) = cos17

⇒

=

[sin^{2}θ + cos^{2}θ = 1]

=

=

=

=

=

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