Q. 51 C5.0( 1 Vote )

If possible, usin

Answer :

Let A =

To apply elementary row transformations we write:

A = IA where I is the identity matrix

We proceed with operations in such a way that LHS becomes I and the transformations in I give us a new matrix such that

I = XA

And this X is called inverse of A = A-1

Note: Never apply row and column transformations simultaneously over a matrix.

So we have:

Applying R2 R2 – (5/2)R1

Applying R3 R3 - R2

Applying R1 R1 + R2


Applying R2 R2 - 5R3


Applying R1 R1 + 2R3


Applying R1 (1/2)R1 and R3 2R3


As we got Identity matrix in LHS.

A-1 =

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