Q. 51 C5.0( 1 Vote )

# If possible, usin

Let A = To apply elementary row transformations we write:

A = IA where I is the identity matrix

We proceed with operations in such a way that LHS becomes I and the transformations in I give us a new matrix such that

I = XA

And this X is called inverse of A = A-1

Note: Never apply row and column transformations simultaneously over a matrix.

So we have: Applying R2 R2 – (5/2)R1 Applying R3 R3 - R2 Applying R1 R1 + R2 = Applying R2 R2 - 5R3 = Applying R1 R1 + 2R3 = Applying R1 (1/2)R1 and R3 2R3 = As we got Identity matrix in LHS.

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