Q. 37 B5.0( 1 Vote )

Find inverse, by

Answer :

Let B =


To apply elementary row transformations we write:


B = IB where I is the identity matrix


We proceed with operations in such a way that LHS becomes I and the transformations in I give us a new matrix such that


I = XB


And this X is called inverse of B = B-1


So we have:



Applying R2 R2 + 2R1



As we got all zeroes in one of the row of matrix in LHS.


So by any means we can make identity matrix in LHS.


inverse of B does not exist.


B-1 does not exist. …ans


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