Two chords AB and

Formula used.

⇒ Mid-point theorem.

Line joining mid-point of 2 sides of triangle is half of 3^rd side of triangle

⇒ Perpendicular to chord divides the chord in 2 equal parts

Solution

As AB and AC are tangents for smaller circle

And Chords for bigger circle

The perpendicular of tangents passes through centre

And radius of smaller circle act as perpendicular to chord

Perpendicular of chord divides it into equal parts

∴ P and Q are mid-points of AB and AC

Join BC to form Δ ABC

As P and Q are mid-points of AB and AC

By mid-point theorem

Line joining mid-point of 2 sides of triangle is half of 3^rd side

Hence;

PQ = 1/2 BC