# Two circles have

O is the point the two circles meet

AO and AP are the radius of circle A

BO and BQ are the radius of circle B

POA = BOQ (Vertically Opposite)

POA = OPA (Δ AOP is an isosceles triangle)

BOQ = BQO (Δ BOQ is an isosceles triangle)

So combining the above two relations we can say

OPA = BQO

Hence the above two angles forms a pair of alternate interior angle

So we say AP BQ

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