Answer :


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O is the point the two circles meet


AO and AP are the radius of circle A


BO and BQ are the radius of circle B


POA = BOQ (Vertically Opposite)


POA = OPA (Δ AOP is an isosceles triangle)


BOQ = BQO (Δ BOQ is an isosceles triangle)


So combining the above two relations we can say


OPA = BQO


Hence the above two angles forms a pair of alternate interior angle


So we say AP BQ


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