Q. 12 E4.4( 7 Votes )

# The lengths

Answer :

A and B are the centre of the two circles

CD is the common tangent

Radius of circle A = 8 cm

Radius of circle B = 3 cm

AB = 13 cm

Since ED∥ AB so

ED = 13 cm

EC = (8-3) = 5cm

Applying Pythagoras theorem in Δ CED we get

Length of tangent = √(13^{2}-5^{2})

⇒ Length of tangent = √ 144 = 12 cm

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