# The tangent drawn at points P and Q on the circumference of a circle intersect at A. If ∠PAQ = 60°, let us find the value of ∠APQ.

PAQ = 60

AQ = AP (Tangent drawn from an external source to the same circle are always equal in length)

So Δ PQA is isosceles triangle

AQP = APQ = x (Let)

Since sum of interior angles of a triangle = 1800,so we can say,

2x + 600 = 1800

2x = 1200

x = 600

APQ = 600

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