Q. 12 A3.9( 7 Votes )

# In the adjoining figure O is the centre and BOA is a diameter of the circle. A tangent drawn to a circle at the point P intersects the extended BA at the point T. If ∠PBO = 30°, let us find the value of ∠PTA.

PBO = 300 (Given)

OPB = 300 (Δ PBO is an isosceles triangle)

OPT = 900 (Tangents are perpendicular to the line joining the centre of the circle)

BPT = (900 + 300) = 1200

PTA = 1800–(1200 + 300) = 300 (Sum of interior angles of Δ BPT)

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