Answer :

(i) Given:
 

When C = 0 then F = 32,

And

When C = -10 then
F = 9(-2) + 32
  = - 18 + 32 
= 14

Now plotting the two points (0, 32) and (-10, 14)


(ii) Putting the value of C = 30 in F = () C + 32, we get


F = × 30 + 32

F = 54 + 32

F = 86

(iii) Putting the value of F = 95 in F = ()C + 32, we get


95 = ()C + 32


()C = 95 - 32


C = 63 × 


C = 35


(iv) After putting the value of F = 0 in


F = () C + 32,


We get:


0 = () C + 32


() = -32


C = -32 × 5/9


C =


Putting the value of C = 0 in


F = () C + 32,


We get:


F = () × 0 + 32


F = 32


(v) We have to find when F = C


Hence,


After putting F = C in


F = ()C + 32,


We get:


F = ()F + 32


F –  ×F = 32


F = 32


F = – 40


Therefore at value -40,


Fahrenheit and Celsius both are numerically the same.

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