# The taxi fare in a city is as follows: For the first kilo-meter the fare is Rs 8 and for the subsequent distance it is Rs 5 per km. Taking the distance covered as x km and total fare as Rs y, write a linear equation for this information, and draw its graph.

Total fare of the taxi = y

Total distance covered = x

Fare for the subsequent distance after 1st kilometer = Rs 5

Fare for 1st kilometer = Rs 8

As per the question,

Total fare = fare of 1st km + Fare of subsequent km x Distance covered
Now for first km, Fare = Rs. 8
For 2nd km, Fare = 8 + 5
For 3rd km, Fare = 8 + 2 × 5
And so on,
Let total fare by y and distance travel be x.
We can see that x is one less than the number of km travelled in total. So,
y = 8 + 5 (x - 1)
= 8 + 5x - 5
= 5x + 3

Now for plotting graph of the given linear equation, we would need different points, So the two points two plot are A(0, 3) and B(1,8). By joining these points we will get the graph of the linear equation. Note: AS it involves Cost on y-axis So please ignore the negative portion of the graph for calculation purpose.

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