Q. 14.2( 314 Votes )

Use suitable iden

Answer :

(i) (x + 4) (x + 10)

Using identity,

(x + a) (x + b) = x2 + (a + b)x + ab

In (x + 4) (x + 10), a = 4 and b = 10

Now,

(x + 4) (x + 10) = x2 + (4 + 10)x + (4 × 10)

= x2 + 14x + 40


(ii) (x + 8) (x - 10)

Using identity,

(x + a) (x + b) = x2 + (a + b) x + ab

Here, a = 8 and b = -10

(x + 8) (x – 10) = x2 + {8 + (-10)} x + {8 × (-10)}

= x2 + (8 – 10)x – 80

= x2 – 2x – 80


(iii) (3x + 4) (3x - 5)

Using identity,

(x + a) (x + b) = x2 + (a + b) x + ab

Here, x = 3x, a = 4 and b = -5

(3x + 4) (3x – 5) = (3x)2 + {4 + (-5)} 3x + {4 × (-5)}

= 9x2 + 3x (4 – 5) – 20

= 9x2 – 3x – 20


(iv)

Using identity,

(x + y) (x – y) = x2 – y2

Here, x = y2 and y =




(v) (3 - 2x) (3 + 2x)

Using identity,

(x + y) (x – y) = x2 – y2

Here, x = 3 and y = 2x

(3 – 2x) (3 + 2x) = 32 – (2x)2

= 9 – 4x2

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