Q. 8

# The total surface

Answer :

Given,

Total surface area of hollow cylinder = 338π cm^{2}

Height = 10 cm

External radius R = 8 cm

Let internal radius = r cm

∴ 2πRh+2πrh+2π(R^{2}-r^{2}) = 338π

=

=80+10r+(8+r)(8-r) =169

= 10r+64-8r+8r-r^{2} = 89

=r^{2}-10r+25 = 0

= r(r-5) -5(r-5) =0

= r = 5 cm

∴ Thickness of hollow cylinder = (R-r) = 8-5 = 3 cm

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