Q. 8
The total surface
Answer :
Given,
Total surface area of hollow cylinder = 338π cm2
Height = 10 cm
External radius R = 8 cm
Let internal radius = r cm
∴ 2πRh+2πrh+2π(R2-r2) = 338π
=
=80+10r+(8+r)(8-r) =169
= 10r+64-8r+8r-r2 = 89
=r2-10r+25 = 0
= r(r-5) -5(r-5) =0
= r = 5 cm
∴ Thickness of hollow cylinder = (R-r) = 8-5 = 3 cm
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