Answer :


Given,


Total surface area of hollow cylinder = 338π cm2


Height = 10 cm


External radius R = 8 cm


Let internal radius = r cm


2πRh+2πrh+2π(R2-r2) = 338π


=


=80+10r+(8+r)(8-r) =169


= 10r+64-8r+8r-r2 = 89


=r2-10r+25 = 0


= r(r-5) -5(r-5) =0


= r = 5 cm


Thickness of hollow cylinder = (R-r) = 8-5 = 3 cm


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