Q. 144.3( 6 Votes )

# Twenty cylindrica

Answer :

Given,

Diameter of one pillar = .50m

Radius of pillar =

Height of each pillar = 4m

Curved surface area of one pillar = 2πrh = ^{2}

Area of 20 pillars = 20×6.28 = 125.60 m^{2}

Cost of cleaning 1 m^{2} area = Rs. 2.50

∴cost of cleaning 125.60 m^{2} = 125.60×2.50 = Rs 314.28.

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