Answer :

In case (i)


2πr= a1


= r = a1/2π


= h1 = a2


So, v1 = πr2h = π×(a1/2π)2h = a12a2/4π…………..(1)


In case (ii)


2πr = a2


= r = a2/2π and h = a1


So, v2 = πr2h = π× (a2/4π)2a1 = a22a1/4π……………….(2)


From equations 1 and 2 …


= a2v1 = a1v2


= v1/a1 = v2/a2 ( so both options (B) and (D) are correct.)

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