Q. 114.5( 12 Votes )

# The dimensions of

Answer :

Given,

Ratio of dimensions of rectangular box = 2:3:4

Let dimensions are = 2x ,3x , 4x

So, total surface area of box = 2(6x^{2}+12x^{2}+8x^{2}) = 52 x^{2}

Let, c_{1} = cost of covering at rate Rs. 8 per m^{2}

C_{1} = 8×52x^{2}

Let c_{2} = cost of covering at rate Rs.9.50 per m^{2}

C_{2} = 9.50× 52x^{2}

= C_{2} – C_{1} = 1248 (given)

= 52x^{2}×9.50 – 52x^{2}×8 = 1248

= 52x^{2} =

= x^{2} =

= x = 4

Hence dimensions of box are = 2x = 2×4 = 8 cm

= 3x = 3×4 = 12 cm

=4x= 4×4 = 16cm

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