Answer :

Let Height of the building is AD, Height of the tower is BC.

Given, ∠CDE = 60^{o}, ∠EDB = 45^{o}. AD = 7.

in BDA,

∠DBA = 45^{o}

AB = AD

AB = 7

in CDE,

∠EDC = 60^{o}

EC = 7√3

Height of the tower =

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