A 12 m high tree breaks due to wind such that its top touches the ground and makes an angle of 60° with the ground. Find at what height from the earth has the tree broken by the wind (√3 = 1.732)?
Let AB is the Height of the tree, ED = h is the Height of the broken tree, CE is the Length of broken part.
Given, ∠ECD = 60o, AB = 12.
2CE + CE√3 = 24
CE = 24(2 – √3)
DE = 12 – 48 + 24√3
DE = 12( – 3 + 2√3)
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