Answer :

Let AB is the Height of the tree, ED = h is the Height of the broken tree, CE is the Length of broken part.

Given, ∠ECD = 60^{o}, AB = 12.

2CE + CE√3 = 24

CE = 24(2 – √3)

DE = 12 – 48 + 24√3

DE = 12( – 3 + 2√3)

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