Q. 14

# Form the differential equation of all circles which pass through origin and whose centres lie on y-axis

To find: differential equation of all circles which pass through origin and centre lies on y axis

Assume a point (0, k) on the y axis

Therefore, the radius of circle is given as

And the general form of equation of circle is

(x-a)2+(y-b)2=r2

Where (a, b) is the centre and r is radius, now substituting the value in the above equation we get

(x-0)2+(y-k)2=k2

x2+y2-2yk=0 …. (i)

Differentiating both side with respect to x

Formula:

Substituting the value of k in eq(i)

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