# Find each of the

By using horizontal method,

We have;

= (x3 – 2x2 + 5) × (4x – 1)

= 4x(x3 – 2x2 + 5) – 1(x3 – 2x2 + 5)

= 4x4 – 8x3 + 20x – 1x3 + 2x2 – 5

By arranging the expression in the form of descending powers of x,

We get;

= 4x4 – 8x3 – x3 + 2x2 + 20x – 5

= 4x4 – 9x3 + 2x2 + 20x – 5

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