Q. 113.9( 7 Votes )

In a vessel of be

Answer :

Let the mixture of syrup and water is “x” litres.


So,


Volume of syrup in the mixture


Volume of water in the mixture


Let “y” = Volume of mix taken out = Volume of water added


When a part of drink is taken out:


In the drink the ratio will remain same:


So,


Volume of syrup is


Volume of water is


After a part is taken out:


Volume of syrup in vessel


Volume of water in vessel


After water is added,


Volume of water


According to the question:


Volume of water added = volume of syrup




2x – 2y + 7y = 5x – 5y


2x + 5y = 5x – 5y


2x + 5y = 5x – 5y


5y + 5y = 5x – 2x


10y = 3x



Hence the volume of water added is 3/10 part of the vessel.


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