Answer :

Let the mixture of syrup and water is “x” litres.

So,

Volume of syrup in the mixture

Volume of water in the mixture

Let “y” = Volume of mix taken out = Volume of water added

When a part of drink is taken out:

In the drink the ratio will remain same:

So,

Volume of syrup is

Volume of water is

After a part is taken out:

Volume of syrup in vessel

Volume of water in vessel

After water is added,

Volume of water

According to the question:

Volume of water added = volume of syrup

⇒ 2x – 2y + 7y = 5x – 5y

⇒ 2x + 5y = 5x – 5y

⇒ 2x + 5y = 5x – 5y

⇒ 5y + 5y = 5x – 2x

⇒ 10y = 3x

Hence the volume of water added is 3/10 part of the vessel.

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