Answer :
In the given figure:
Radius AB = 17cm
Chord CD = 17cm
Now we draw a perpendicular bisector of CD from A which is AB
Hence CE = DE = 8cm
We have to find the distance of chord from centre i.e. AE
In the triangle ACE
AC2 = AE2 + EC2
Therefore AE2 = 172– 82
AE2 = 225
AE = 15cm
Hence the distance of chord from the centre is 15cm
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