Q. 25.0( 1 Vote )

The radius of a c

Answer :

In the given figure:


Radius AB = 17cm


Chord CD = 17cm


Now we draw a perpendicular bisector of CD from A which is AB


Hence CE = DE = 8cm


We have to find the distance of chord from centre i.e. AE


In the triangle ACE


AC2 = AE2 + EC2


Therefore AE2 = 172– 82


AE2 = 225


AE = 15cm


Hence the distance of chord from the centre is 15cm


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