The radius of a c

In the given figure:

Radius AB = 17cm

Chord CD = 17cm

Now we draw a perpendicular bisector of CD from A which is AB

Hence CE = DE = 8cm

We have to find the distance of chord from centre i.e. AE

In the triangle ACE

AC² = AE² + EC²

Therefore AE² = 17²– 8²

AE² = 225

AE = 15cm

Hence the distance of chord from the centre is 15cm