Q. 25.0( 1 Vote )

# The radius of a c

In the given figure: Chord CD = 17cm

Now we draw a perpendicular bisector of CD from A which is AB

Hence CE = DE = 8cm

We have to find the distance of chord from centre i.e. AE

In the triangle ACE

AC2 = AE2 + EC2

Therefore AE2 = 172– 82

AE2 = 225

AE = 15cm

Hence the distance of chord from the centre is 15cm

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