Answer :

As ABCD is a cyclic quadrilaterals, sum of all angles = 360°

As AB is parallel to CD

∠ADC = 180 – ∠DAB = 80° as they are interior angles on the same side.

As angle subtended by chord BD on circumference = 100°

Therefore ∠BCD = 100°

As ∠BCD and ∠ABC are interior angles

∠ABC = 180 – ∠BCD = 80°

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