Answer :


The figure is attached above


A is the centre of the circle.


AB is the radius = 15 cm


CD is the chord = 18 cm.


We need to find the distance of the chord from the centre i.e. AE


In this circle, we draw the perpendicular


We know that perpendicular drawn from the centre to the chord, will bisect the chord, such that CE = ED = = 9 cm


Now,


In ΔAEC,


Applying Pythagoras theorem,


AC2 = AE2 + EC2


AE2 = AC2 – EC2


AE2 = (15cm)2–(9cm)2


AE2 = 225 – 81 = 144


AE = √144


AE = 12 cm


The chord is 12cm away from the center of the circle.


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