Q. 73.9( 8 Votes )
Which term of the GP√3, 3, 3√3… is 729?
Answer :
Given GP is √3, 3, 3√3….
The given GP is of the form, a, ar, ar2, ar3….
Where r is the common ratio.
First term in the given GP, a1 = a = √3
Second term in GP, a2 = 3
Now, the common ratio, 
Let us consider 729 as the nth term of the GP.
Now, nth term of GP is, an = arn – 1
729 = √3 (√3) n – 1
√3n = √312
n = 12
So, 729 is the 12th term in GP.
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