# Which term of the

Given GP is √3, 3, 3√3….

The given GP is of the form, a, ar, ar2, ar3….

Where r is the common ratio.

First term in the given GP, a1 = a = √3

Second term in GP, a2 = 3

Now, the common ratio,  Let us consider 729 as the nth term of the GP.

Now, nth term of GP is, an = arn – 1

729 = √3 (√3) n – 1

√3n = √312

n = 12

So, 729 is the 12th term in GP.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

The product of thRD Sharma - Mathematics

Express <imRS Aggarwal - Mathematics

If a, b, c are inRS Aggarwal - Mathematics

Express <imRS Aggarwal - Mathematics

Prove that RS Aggarwal - Mathematics

If a, b, c are inRS Aggarwal - Mathematics

The sum of n termRS Aggarwal - Mathematics

If a, b, c, d areRS Aggarwal - Mathematics

Evaluate :
</p
RS Aggarwal - Mathematics

The first term ofRS Aggarwal - Mathematics