Q. 73.9( 8 Votes )

Which term of the GP√3, 3, 3√3… is 729?

Answer :

Given GP is √3, 3, 3√3….

The given GP is of the form, a, ar, ar2, ar3….

Where r is the common ratio.

First term in the given GP, a1 = a = √3

Second term in GP, a2 = 3

Now, the common ratio,

Let us consider 729 as the nth term of the GP.

Now, nth term of GP is, an = arn – 1

729 = √3 (√3) n – 1

√3n = √312

n = 12

So, 729 is the 12th term in GP.

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