Q. 64.3( 6 Votes )
Which term of the GP 
is -128?
Answer :
Given GP is 
….
The given GP is of the form, a, ar, ar2, ar3….
Where r is the common ratio.
The first term in the given GP, 
The second term in GP, 
Now, the common ratio, 
Let us consider -128 as the nth term of the GP.
Now, nth term of GP is, an = arn – 1
n – 1
2)n = 1024 = (-2)10
n = 10
So, -128 is the 10th term in GP.
Rate this question :
Calculations of Geometrical Isomers59 mins
Geometric Progression58 mins
Learn Sum of Series by Method of Difference34 mins
Quiz on Geometric progression6 mins
Introduction to Geometrical Isomerism57 mins
Geometrical Isomerism in Cyclic Compounds49 mins
All formulas of Harmonic Progression36 mins
Practise Test on Harmonic Progression37 mins
Different Categories of Geometrical Isomerism48 mins
Arithmetic progression | Understanding the basics45 mins
The product of three numbers in G.P. is 216. If 2, 8, 6 be added to them, the results are in A.P. Find the numbers.
RD Sharma - MathematicsFind three number in G.P. whose sum is 38 and their product is 1728.
RD Sharma - MathematicsThe sum of the first three terms of a G.P. is 
, and their product is 1. Find the common ratio and the terms.
The sum of first three terms of a G.P. is 
, and their product is – 1. Find the G.P.
Express 
as a rational number.
If a, b, c are in GP, prove that (a2 + b2), (ab + bc), (b2 + c2) are in GP.
RS Aggarwal - MathematicsExpress 
as a rational number.
Prove that 
If a, b, c are in GP, prove that a2, b2, c2 are in GP.
RS Aggarwal - MathematicsThe sum of n terms of a progression is (2n – 1). Show that it is a GP and find its common ratio.
RS Aggarwal - Mathematics