Q. 133.7( 3 Votes )
Find the 4th term from the end of the GP
.
Answer :
The given GP is 
.→ (1)
The first term in the GP, 
The second term in the GP, 
The common ratio,
r = 3
The last term in the given GP is an = 162.
Second last term in the GP = an-1 = arn-2
Starting from the end, the series forms another GP in the form,
arn-1, arn-2, arn-3….ar3, ar2, ar, a → (2)
Common ratio of this GP is 
.
So,
.
So, 4th term of the GP (2),
a4 = ar3
= 
Hence, the 4th term from the end of the given GP is 6.
Rate this question :
Geometric Progression58 mins
Calculations of Geometrical Isomers59 mins
Quiz on Geometric progression6 mins
Introduction to Geometrical Isomerism57 mins
Geometrical Isomerism in Cyclic Compounds49 mins
Practise Test on Harmonic Progression37 mins
All formulas of Harmonic ProgressionFREE Class
Different Categories of Geometrical Isomerism48 mins
General Term of Miscellaneous progression46 mins
Arithmetic progression | Understanding the basics45 mins
The product of three numbers in G.P. is 216. If 2, 8, 6 be added to them, the results are in A.P. Find the numbers.
RD Sharma - MathematicsFind three number in G.P. whose sum is 38 and their product is 1728.
RD Sharma - MathematicsThe sum of the first three terms of a G.P. is 
, and their product is 1. Find the common ratio and the terms.
The sum of first three terms of a G.P. is 
, and their product is – 1. Find the G.P.
Express 
as a rational number.
If a, b, c are in GP, prove that (a2 + b2), (ab + bc), (b2 + c2) are in GP.
RS Aggarwal - MathematicsExpress 
as a rational number.
Prove that 
If a, b, c are in GP, prove that a2, b2, c2 are in GP.
RS Aggarwal - MathematicsThe sum of n terms of a progression is (2n – 1). Show that it is a GP and find its common ratio.
RS Aggarwal - Mathematics