Q. 4 B5.0( 1 Vote )

# Prove that follow

Let be a rational number.

Therefore , where g. c. d(a, b) = 1 and a, b N.

Now, squaring both sides

……. eq (1)

15 | a2

15 | a

Now, let a = 15k, k N

So, b = 15k

15 | b

It is a contradiction as g. c. d(a, b) = 1

So, our assumption is wrong.

Therefore, is irrational.

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