Q. 4 B5.0( 1 Vote )
Prove that follow
Answer :
Let be a rational number.
Therefore , where g. c. d(a, b) = 1 and a, b N.
Now, squaring both sides
……. eq (1)
15 | a2
15 | a
Now, let a = 15k, k N
So, b = 15k
15 | b
It is a contradiction as g. c. d(a, b) = 1
So, our assumption is wrong.
Therefore, is irrational.
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