Q. 1 C

# Find g. c. d10211, 2517

10211, 2517

Here, 10211 > 2517

10211 = 3517 × 4 + 143

2517 = 143 × 17 + 86

143 = 86 × 1 + 57

86 = 57 × 1 + 29

57 = 29 × 1 + 28

29 = 28 × 1 + 1

28 = 1 × 28 + 0

The last non- zero remainder is 1.

Therefore, g. c. d (10211, 2517) = 1

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