Q. 384.0( 4 Votes )

Find the smallest number of six digits divisible by 18, 24 and 30

Answer :

To find the smallest number of six digits divisible by 18, 24 and 30 we find the l.c.m. of them.

18 = 3 × 3 × 2


24 = 2 × 2 × 2 × 3


30 = 3 × 2 × 5


Therefore, l.c.m.(18, 24, 30) = 2 × 2 × 2 × 3 × 3 × 5 = 360


We know that the smallest six digit number is 100000.


Dividing 100000 by 18 = = 277. 77


So, the integer bigger and nearest to 277. 77 is 278.


Therefore, required integer = 278 × 360 = 100080


So, the smallest number of six digits divisible by 18, 24 and 30


is 100080.


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