Q. 5

# Using B = μ0 H find the ratio E0/H0 for a plane electromagnetic wave propagating through vacuum. Show that is has the dimensions of electric resistance. This ratio is a universal constant called the impedance of free space.

Given: The magnetic field density and the magnetic field strength

as related by the relation

where B is the magnetic field density, μm is the relative magnetic

permeability of the material and depends on the nature of the

material or the medium and H is the magnetic field strength which

tells upto what extent a material can be magnetized.

…. (i)

where B0 is the field intensity in free space(vacuum), H0 is the

strength in free space and μ0 is the magnetic permeability of free

space. μ0 is a universal constant and its value is 4π × 10-7 T m A-1.

We can define a relation between the electric field and magnetic field

of an electromagnetic wave travelling in vacuum. It is

…. (ii)

where E0 is the electric field density and C is the speed of light in

vacuum.

From (i) and (ii)

…. (iii)

To find the dimension of , we will find the dimension of the

quantity in the R.H.S.

The dimension of C is [L T-1] because it is the speed.

To find the dimension of , we need to consider the Biot Savart’s

law which gives the magnetic field due to a current carrying

conductor. According to Biot Savart law

…. (iv)

where i is the current in the conductor, L is the length of conductor and R is the distance between conductor and point where field is to be found.

The scalar form of the above equation will be simply

…. (v)

From (v)

the dimensions of μ0 will be the dimensions of R.H.S

dimension of B= [M T-2 A �-1]

dimension of R2=[L2]

dimension of L=[L]

dimension of i=[A]

dimension of R.H.S

Therefore dimension of μ0 is .

Now the dimension of R.H.S of eq(iii) will be dimension of C × dimension of μ0

dimension of

As the dimensions of electric resistance given by Ohm’s Law(V=iR) is

Therefore has the same dimensions as that of electrical resistance.

Also the value of is a constant because the R.H.S of eq(iii) is the

product of 2 universal constants.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Source of Electromagnetic wave6 mins
Back to 11th | Interactive Quiz: Waves (part-2)52 mins
Electromagnetic Induction50 mins
Back to 11th | Interactive Quiz: Waves (part-1)49 mins
S.H.M.51 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses