Q. 3
Let’s find the value of
by calculation if
or, 
or, 
or,
[by transposition]

[With the help of the identity No. VI]

Answer :
Given,
Multiplying both side by ‘x’
⇒ x2 + 1 = -x
⇒ x2 + x + 1 = 0
Now,
x3 – 1
Using x3 – y3 = (x – y)(x2 + xy + y2)
= (x – 1)(x2 + x + 1)
= (x – 1) × 0
= 0
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