Q. 3

# Let’s find the value of by calculation ifor, or, or, [by transposition][With the help of the identity No. VI]

Given,

Multiplying both side by ‘x’

x2 + 1 = -x

x2 + x + 1 = 0

Now,

x3 – 1

Using x3 – y3 = (x – y)(x2 + xy + y2)

= (x – 1)(x2 + x + 1)

= (x – 1) × 0

= 0

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