Q. 3

Let’s find the value of by calculation if

or,

or,

or, [by transposition]



[With the help of the identity No. VI]



Answer :

Given,



Multiplying both side by ‘x’



x2 + 1 = -x


x2 + x + 1 = 0


Now,


x3 – 1


Using x3 – y3 = (x – y)(x2 + xy + y2)


= (x – 1)(x2 + x + 1)


= (x – 1) × 0


= 0


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