Answer :
Given,
Multiplying both side by ‘a’
⇒ a2 + 9 = 3a
⇒ a2 – 3a + 9 = 0
Now,
a3 + 27
= a3 + 33
Using x3 + y3 = (x + y) (x2 – xy + y2)
= (a + 3) (a2 – 3a + 32)
= (a + 3) (a2 – 3a + 9)
= (a + 3) × 0
= 0
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