Q. 32

pH of 0.08 mol dm

Answer :

Given, pH =2.85 and C =0.08 mol dm-3

Now since HOCl is a weak acid its dissociation will be given as-

We know that;

pH = -log [H+]

-2.85 = log [H+]

[H+] = antilog (-2.85)

[H+] = 1.41 × 10-3

We also know that, for a weak mono basic acid-

(On squaring both sides)

Ka = 2.5 × 10-5

Hence the ionization constant of HOCl will be 2.5 × 10-5

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

Calculate the pH NCERT - Chemistry Part-I

The ionization coNCERT - Chemistry Part-I

The pH of milk, bNCERT - Chemistry Part-I

Assuming completeNCERT - Chemistry Part-I