Given; NH3 + BF3→ H3N: BF3
Lewis acid in this reaction is NH3 (N=1s22s22p1)as it has a lone pair of e- to donate in its p-orbital and Lewis base Is BF3 as p-orbital of Boron is empty(B=1s22s22p1) so it will accept lone pair from N and form a dative bond. This is explained by lewis electronic theory. The Hybridisation of N is sp3 and B is sp2.
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