Q. 33

# Calculate the pH

Given, pH of solution A = 6

[H+] of solution A = 10-6 mol/lit.

pH of solution B = 4

[H+] of solution B = 10-4 mol/lit.

On mixing 1L of each solution we will get total 2L of Solution.

Amount of [H+] in 1L: solution A = 10-6× 1L = 10-6

: Solution B = 10-4 × 1L = 10-4

Total [H+] in Solution = 10-6 + 10-4

=10-4 (1+0.01/2)

=10-4× 1.01/2

=5×10-5 mol/L

pH = -log[H+]= -log[5×10-5]

=-log(5) + (-5log10)

=-log5 + 5 =4.3

The pH of the Solution formed by mixing will be 4.3

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