Q. 33

Calculate the pH

Answer :

Given, pH of solution A = 6

[H+] of solution A = 10-6 mol/lit.


pH of solution B = 4


[H+] of solution B = 10-4 mol/lit.


On mixing 1L of each solution we will get total 2L of Solution.


Amount of [H+] in 1L: solution A = 10-6× 1L = 10-6


: Solution B = 10-4 × 1L = 10-4


Total [H+] in Solution = 10-6 + 10-4



=10-4 (1+0.01/2)


=10-4× 1.01/2


=5×10-5 mol/L


pH = -log[H+]= -log[5×10-5]


=-log(5) + (-5log10)


=-log5 + 5 =4.3


The pH of the Solution formed by mixing will be 4.3


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