Q. 1 H4.2( 29 Votes )

# Assign oxidation number to the underlined elements in each of the following species:

KAl(__S__O_{4})_{2}.12 H_{2}O

Answer :

Let the oxidation number(O.N.) of S be ‘x’

We know that,

O.N. of K = + 1

O.N. of H = + 1

O.N. of O = -2

O.N. of Al = + 3

Therefore, we have,

1(+ 1) + 1(+ 3) + 2(x) + 8(-2) + 24(+ 1) + 12(-2) = 0

1 + 3 + 2x-16 + 24-24 = 0

X = + 6

The O.N. of S is + 6.

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