Answer :
Let the oxidation number(O.N.) of S be ‘x’
We know that,
O.N. of K = + 1
O.N. of H = + 1
O.N. of O = -2
O.N. of Al = + 3
Therefore, we have,
1(+ 1) + 1(+ 3) + 2(x) + 8(-2) + 24(+ 1) + 12(-2) = 0
1 + 3 + 2x-16 + 24-24 = 0
X = + 6
The O.N. of S is + 6.
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
