Answer :

Following the steps as in part (A), we have the oxidation half reaction equation as:-

SO2(g) + 2H2O SO42-(aq) + 4H+(aq) + 2e-

And the reduction half reaction as:-

Cr2O72-(aq) + 14H+(aq) + 6e- 2Cr3+(aq) + 7H2O

Multiplying the oxidation half reaction by 3 and then adding it to the reduction half reaction, we have the net balanced redox reaction equation as:-

Cr2O72-(aq) + 3 SO2(g) + 2H+(aq) 2Cr3+(aq) + 3SO42-(aq) + H2O

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