Q. 1 G4.3( 24 Votes )

# Assign oxidation number to the underlined elements in each of the following species:

H_{2}__S___{2}O_{7}

Answer :

Let the oxidation number(O.N.) of S be ‘x’

We know that,

O.N. of H = + 1

O.N. of O = -2

Therefore, we have,

2(+ 1) + 2(x) + 7(-2) = 0

2x = 12

X = + 6

The O.N. of S is + 6.

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