Answer :

Given:- Parallelogram OABC

To Prove:- AC2 + OB2 = OA2 + AB2 + BC2 + CO2

Proof:- Let, O at origin


Distance/length of AC

By triangular law:-

the the vectors form sides of triangle

As AB = OC and BC = OA

From figure


Similarly, again from figure



Adding equation (i) and (ii)


Take RHS

OA2 + AB2 + BC2 + CO2


Thus from equation (iii) and (iv), we get


Hence proved

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

Write a unit vectMathematics - Board Papers

Fill in the blankMathematics - Exemplar

A and B areMathematics - Board Papers

L and M are two pMathematics - Board Papers

The scalar producMathematics - Board Papers

A vector <span laMathematics - Exemplar